初二数学分式题:已知x-y-z=0,y-z=0,且xyz≠0.
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初二数学分式题:已知x-y-z=0,y-z=0,且xyz≠0.
已知x-y-z=0,y-z=0,且xyz≠0.
求 (1998x^2+1999y^2-2000z^2)/(1998x^2-1999y^2+2000z^2) 的值.
已知x-y-z=0,y-z=0,且xyz≠0.
求 (1998x^2+1999y^2-2000z^2)/(1998x^2-1999y^2+2000z^2) 的值.
![初二数学分式题:已知x-y-z=0,y-z=0,且xyz≠0.](/uploads/image/z/17523606-30-6.jpg?t=%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E5%88%86%E5%BC%8F%E9%A2%98%EF%BC%9A%E5%B7%B2%E7%9F%A5x-y-z%3D0%2Cy-z%3D0%2C%E4%B8%94xyz%E2%89%A00.)
y-z=0,y=z
x-y-z=0,x=y+z=2z
(1998x^2+1999y^2-2000z^2)/(1998x^2-1999y^2+2000z^2)
=(1998*4z^2+1999z^2-2000z^2)/(1998*4z^2-1999z^2+2000z^2
=(1998*4-1)/(1998*4+1)
=7991/7993
x-y-z=0,x=y+z=2z
(1998x^2+1999y^2-2000z^2)/(1998x^2-1999y^2+2000z^2)
=(1998*4z^2+1999z^2-2000z^2)/(1998*4z^2-1999z^2+2000z^2
=(1998*4-1)/(1998*4+1)
=7991/7993
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