计算分式乘除1、x^2-2x+1/x^2 2、2/2a+3+3/2a-3 3、x^2-2x+1/x^2-1÷x-1/x^
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/20 01:10:01
计算分式乘除
1、x^2-2x+1/x^2 2、2/2a+3+3/2a-3
3、x^2-2x+1/x^2-1÷x-1/x^2+x
1、(x^2-2x+1)/(x^2 ) 2、(2/2a+3)+(3/2a-3)+(2a+15)/(4a^2-9)
3、(x^2-2x+1)/(x^2-1)÷(x-1)/(x^2+x)
1、x^2-2x+1/x^2 2、2/2a+3+3/2a-3
3、x^2-2x+1/x^2-1÷x-1/x^2+x
1、(x^2-2x+1)/(x^2 ) 2、(2/2a+3)+(3/2a-3)+(2a+15)/(4a^2-9)
3、(x^2-2x+1)/(x^2-1)÷(x-1)/(x^2+x)
(1)
(x^2-2x+1)/x^2
=(x-1)^2/x^2
=[(x-1)/x]^2
(2)
2/(2a+3)+3/(2a-3)+(2a+15)/(4a^2-9)
=2(2a-3)/(4a^2-9)+3(2a+3)/(4a^2-9)+(2a+15)/(4a^2-9)
=(4a+18)/(4a^2-9)
(3)
(x^2-2x+1)/(x^2-1)÷(x-1)/(x^2+x)
=(x-1)^2/[(x+1)(x-1)]÷(x-1)/[x(x+1)]
=(x-1)/(x+1)÷(x-1)/[x(x+1)]
=(x-1)*x(x+1)/[(x+1)(x-1)]
=x
(x^2-2x+1)/x^2
=(x-1)^2/x^2
=[(x-1)/x]^2
(2)
2/(2a+3)+3/(2a-3)+(2a+15)/(4a^2-9)
=2(2a-3)/(4a^2-9)+3(2a+3)/(4a^2-9)+(2a+15)/(4a^2-9)
=(4a+18)/(4a^2-9)
(3)
(x^2-2x+1)/(x^2-1)÷(x-1)/(x^2+x)
=(x-1)^2/[(x+1)(x-1)]÷(x-1)/[x(x+1)]
=(x-1)/(x+1)÷(x-1)/[x(x+1)]
=(x-1)*x(x+1)/[(x+1)(x-1)]
=x
分式:计算1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+...+1/(x-99)(x-100)
分式的乘除.···(1)x²分之x²+x乘x²-1分之x (2) x²-3x分之
分式混合计算(x+1/x^2-x - x/x^2-2x+1)*x
计算:[(-5+x)(-x-5)]² (x+3)²-(x+2)(x-1) (3x-a)(3x+a)(
分式通分:x+1/3x,x/2x+6,x-1/x^2-9
x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程
分式方程1/[x(x+1)]+1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+...+1/[(x+9)(x+
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
分式计算:1/(1-x) -1/(1+x)-2x/(1+x^2)+(-4x^3)/(1+x^4)=?
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)
数学一道繁分式题已知(x^2+x-3)/[(x-1)(x-2)(x-3)]=A/(x-1)+B/(x-2)+C/(x-3
繁分式 已知(x²+x-3)\[(x-1)(x-2)(x-3)]=A\(x-1)+B\(x-2)+C\(x-3