LOG2(X+Y)=LOG2X+LOG2Y求X+Y的范围
log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,
设点P(X,Y)在直线x+y=1位于第一象限,则log2x+log2y的最大值是?
已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
(2014•宝山区二模)已知log2x+log2y=1,则x+y的最小值为22
求函数y=log1\2(1-2x-x^2)的值域 求满足不等式log2(3x-5)<log2x+1的x取值范围
函数Y=log2(x^2+1)-log2x的值域
已知log2[log4(log3x)]=log3[log5(log2y)]=0,求4更号x-y^1/5
函数图形变换已知 y=log2x的图像如图所示:试求不等式:log2(-2)小于x+1成立的x的取值范围.
已知log2(log3(log4x))=0,且log4(log2y)=1.求根号x*y^3/4的值在线等啊.
若log2(log3(log4x)=log3(log4(log2y)=log4(log2(log3z)=0则x+y-z=
y=log2(|x-1|)的图像可由y=log2x如何得到
log2[log3(log4x)]=log3[log4(log2y)]=0,则x+y=______.