化简[sin²(α+π)cos(α+π)]/tan(α+π)cos³(-α-π)tan(-α-2π)
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
求证:[sin^2(π+α)*cos(π/2-α)+tan(2π-α)*cos(-α)]/-sin^2(-α)+tan(
化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α
化简sin³(﹣α)cos(2π+α)tan(2π-α)/sin(α-2π)cos(α-3π/2)-tan(π
若α∈(0,π/6) 比较tan(sinα),tan(cosα),tan(tanα)的大小
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
求证:1-2sinαcosα/cos²α-sin²α=tan(π/4-α)
求证(1-2sinαcosα)/(cos²α-sin²α)=tan(π/4-α)
化简(2cos²α-1)/2tan(π/4+α)sin²(π/4-α)
化简(2cos²α-1)/[2tan(π/4-α)sin²(π/4+α)]
[sin(2π+α)·tan(-α)·cos(-α)]÷[sin(-α)·cos(2π+α)·tan(2π+α)化简
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα