已知x>0,y>0,x≠y,且x+y=x2+y2+xy,求证:1
已知x>y>0,且xy=1,求 (x2+y2)/(x-y)的最小值,
已知x>y,且xy=1,求证:(x2+y2/x-y)≥2根号2
已知x>y>0且xy=1.求x2+y2/x-y的最小值及此时xy的值
已知x,y均为正数,且x>y,求证:2x+1/(x2-2xy+y2)>=2y+3
已知实数x,y满足(x2)+(y2)-xy+2x-y+1=0,求x,y的值
已知实数x、y满足X2+y2-xy+2x-y+1=0,试求x、y的值
已知x.y∈R,求证x2+y2+1≥x+y+xy
已知x>y>0,且xy=1,求(x2+y2)/(x-y)的最小值及相应的x,y的值.
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x
已知实数x、y满足2x2-7xy+3y2=0,求x:y
已知x2+y2-2x+4y+5=0,求(x^4-y^4)/(2x^2+xy-y^2)·[(2x-y)/(xy-y^2)]
已知x2+y2-2x-4y+5=0,则1xy+1(x+1)(y+1)+1(x+2)(y+2)+…+1(x+2010)(y