6x^n+1-14x^n+8x^n-1,(x+3)^2-2(x+3)-8,(2x-1)(3x+2)-20,ab(c^2+
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6x^n+1-14x^n+8x^n-1,(x+3)^2-2(x+3)-8,(2x-1)(3x+2)-20,ab(c^2+d^2)+cd(a^2+b^2)因式分解
这是四道因式分解题
这是四道因式分解题
![6x^n+1-14x^n+8x^n-1,(x+3)^2-2(x+3)-8,(2x-1)(3x+2)-20,ab(c^2+](/uploads/image/z/17809863-15-3.jpg?t=6x%5En%2B1-14x%5En%2B8x%5En-1%2C%28x%2B3%29%5E2-2%28x%2B3%29-8%2C%282x-1%29%283x%2B2%29-20%2Cab%28c%5E2%2B)
1:原式
=x^(n-1)(6x^2-14+8)
1 -1
6 -8
=x^(n-1)(x-1)(6x-8)
2:原式
1 2
1 -4
=(x+3+2)(x+3-4)
=(x+5)(x-1)
3:
6x^2+x-22=0
1 2
6 -11
(x+2)(6x-11)=0
x=-2
x=11/6
4:
abc^2+abd^2+a^2cd+b^2cd
=abc^2+a^2cd+abd^2+b^2cd
=ac(bc+ad)+bd(ad+bc)
=(ad+bc)(ac+bd)
=x^(n-1)(6x^2-14+8)
1 -1
6 -8
=x^(n-1)(x-1)(6x-8)
2:原式
1 2
1 -4
=(x+3+2)(x+3-4)
=(x+5)(x-1)
3:
6x^2+x-22=0
1 2
6 -11
(x+2)(6x-11)=0
x=-2
x=11/6
4:
abc^2+abd^2+a^2cd+b^2cd
=abc^2+a^2cd+abd^2+b^2cd
=ac(bc+ad)+bd(ad+bc)
=(ad+bc)(ac+bd)
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