求∫dx/(a^2sin^2x+b^2cos^2x)解答

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/08/19 18:56:08

∫dx/(a^2sin^2x+b^2cos^2x)
=∫dx/a^2*cos^2x*(tan^2x+b^2/a^2)
=1/a^2∫sec^2xdx/(tan^2x+b^2/a^2)
=1/a^2∫d(tanx)/(tan^2x+(b/a)^2)
=1/a^2*a/b*arctan(ax/b)+C
=(1/ab)*arctan(ax/b)+C

∫sin(x) cos^2(x)dx 求微积分 ∫sin^2(x)cos^4(x) dx 求积分：∫sin^2 (x) /cos^3 (x) dx 求不定积分∫[1/(sin^2 cos^2(x)]dx 求不定积分：| ( sin^2 x / cos^3x ) dx 求微分sin^2x*cos^5x*dx ∫dx/[sin^2(x/2)cos^2(x/2)] ∫sin^2(x)cos^2(x)dx ∫dx/cos^2X+4sin^2X 微积分求解：∫sin^3 (x) cos^2 (x) dx ∫ [cos^3(x)]/[sin^2 (x)]dx ∫sin^3(x)cos^2(x)dx=