计算[(x+2y)²-(x+y)(x-y)-5y²]÷(2x)
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
计算:(1).(-2xy²)*(3x²y)²
分式的乘除法计算::x²-4y²/x²+2xy+y²÷x+2y/x²+
(x+y)²-2(x²-y²)+(y-x)²
计算:(2x+y-1)²
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
化简:1.2x²-y²+(2y²-3x²)-(2y²+x²)
x²-4y² x+2y
1-x²+2xy-y²
|x+2y+3|+(2x+y)²=0求x²-xy+y²