y=sin^2x+sin2x+2cos^x
Y=sin^2x+sin2x+2cos^2x化简
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
求函数Y=sin^4x +cos^4x +sin^2x cos^2x 除以2-sin2x的最小正周期,最大值最小值
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
求函数fx=(sin^4x+cos^4x+sin^2x*cos^2x)/(2-sin2x)
求函数y=[sin2x+sin(2x+π/3)]/[cos2x +cos(2x+π/3)]的最小正周期
设函数f(x)=sin²x+2sin2x+3cos²x 化简
函数y=sin2x-2cos^2x最大值?
y=cos²x+1/2sin2x 求化简
函数y=2cos方x+sin2x的最小值
sin(x+y)sin(x-y)=k,求cos^2x-cos^2y
已知 兀/2 < Y < X< 3兀/4,cos(X+Y)=12/13,sin(X+Y)=-3/5,求sin2X.