解个方程:X^2-Y^2=3 Z^2-Y^2=8 X=Y+30t Z=y+60t 联立这4个解下V1和t
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解个方程:X^2-Y^2=3 Z^2-Y^2=8 X=Y+30t Z=y+60t 联立这4个解下V1和t
![解个方程:X^2-Y^2=3 Z^2-Y^2=8 X=Y+30t Z=y+60t 联立这4个解下V1和t](/uploads/image/z/18187616-56-6.jpg?t=%E8%A7%A3%E4%B8%AA%E6%96%B9%E7%A8%8B%EF%BC%9AX%5E2-Y%5E2%3D3+Z%5E2-Y%5E2%3D8+X%3DY%2B30t+Z%3Dy%2B60t+%E8%81%94%E7%AB%8B%E8%BF%994%E4%B8%AA%E8%A7%A3%E4%B8%8BV1%E5%92%8Ct)
V1是什么?
如果是求Y和t的话:
X^2-Y^2=3变形:(X-Y)(X+Y)=3,再变:
Z^2-Y^2=8变形:(Z-Y)(Z+Y)=8,再变:
再问: 错了,求y ,t
再答: X^2-Y^2=3变形:(X-Y)(X+Y)=3,代入X=Y+30t 有:30t(2Y+30t)=3 Z^2-Y^2=8变形:(Z-Y)(Z+Y)=8,代入Z=y+60t 有:60t(2Y+60t)=8 上下两式相除可得:(2Y+30t)/3(2Y+60t)=1/4,继而有:Y=30t,再代入上面其中之一可得: t=1/30,Y=1(或者t=-1/30,Y=-1,依题意而定)
如果是求Y和t的话:
X^2-Y^2=3变形:(X-Y)(X+Y)=3,再变:
Z^2-Y^2=8变形:(Z-Y)(Z+Y)=8,再变:
再问: 错了,求y ,t
再答: X^2-Y^2=3变形:(X-Y)(X+Y)=3,代入X=Y+30t 有:30t(2Y+30t)=3 Z^2-Y^2=8变形:(Z-Y)(Z+Y)=8,代入Z=y+60t 有:60t(2Y+60t)=8 上下两式相除可得:(2Y+30t)/3(2Y+60t)=1/4,继而有:Y=30t,再代入上面其中之一可得: t=1/30,Y=1(或者t=-1/30,Y=-1,依题意而定)
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