1、已知3x²+xy-2y²=0(x≠0,y≠0)求x/y-y/x-(x²+y²
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1、已知3x²+xy-2y²=0(x≠0,y≠0)求x/y-y/x-(x²+y²)/xy的值
2、已知(a+b-c)/c=(a-b+c)/b=(-a+b+c)/c,求(a+b)(b+c)(c+a)/abc的值
2、已知(a+b-c)/c=(a-b+c)/b=(-a+b+c)/c,求(a+b)(b+c)(c+a)/abc的值
![1、已知3x²+xy-2y²=0(x≠0,y≠0)求x/y-y/x-(x²+y²](/uploads/image/z/18298902-30-2.jpg?t=1%E3%80%81%E5%B7%B2%E7%9F%A53x%26sup2%3B%2Bxy-2y%26sup2%3B%3D0%EF%BC%88x%E2%89%A00%2Cy%E2%89%A00%EF%BC%89%E6%B1%82x%2Fy-y%2Fx-%EF%BC%88x%26sup2%3B%2By%26sup2%3B)
(1)由3x²+xy-2y²=0得:
(x+y)(3x-2y)=0
x=-y或 x=2y/3
x/y-y/x-(x²+y²)/xy
=(x²-y²)/xy-(x²+y²)/xy
=-2y²/xy=-2y/x
把 x=-y或 x=2y/3代入上式有
-2y/x =2或-3
所以x/y-y/x-(x²+y²)/xy的值的2或-3
(2)(a+b-c)/c=(a-b+c)/b=(-a+b+c)/a
=(a+b)/c=(a+c)/b=(b+c)/a
=〔(a+b)+(a+c)+(b+c)〕/(c+b+a)(等式的分子分母分别相加,等式的值不变)
=2
所以(a+b)(b+c)(c+a)/abc
=〔(a+b)/c〕〔(a+c)/b〕〔(b+c)/a〕
=2×2×2
=8
(x+y)(3x-2y)=0
x=-y或 x=2y/3
x/y-y/x-(x²+y²)/xy
=(x²-y²)/xy-(x²+y²)/xy
=-2y²/xy=-2y/x
把 x=-y或 x=2y/3代入上式有
-2y/x =2或-3
所以x/y-y/x-(x²+y²)/xy的值的2或-3
(2)(a+b-c)/c=(a-b+c)/b=(-a+b+c)/a
=(a+b)/c=(a+c)/b=(b+c)/a
=〔(a+b)+(a+c)+(b+c)〕/(c+b+a)(等式的分子分母分别相加,等式的值不变)
=2
所以(a+b)(b+c)(c+a)/abc
=〔(a+b)/c〕〔(a+c)/b〕〔(b+c)/a〕
=2×2×2
=8
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