解方程组x²+2xy+y²=9和(x-y)²-3(x-y)+2=0
方程组{x²+y²=10(1)x²-3xy+2y²=0(2)怎么解
|x+2y+3|+(2x+y)²=0求x²-xy+y²
已知X²-5XY+6Y²=0,求(X²+3XY)\2Y²的值
已知x/y=3,求x²+2xy-3y²/x²-2xy+y²
已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值
x/y=2,求分式x²-xy+3y²/x²+xy+6y²
已知关于x、y的方程组3(x²+y²)-5xy=6;2(x²+y²)+xy=17
一道方程组(要过程)X²+3XY+Y²+2Y=8 2X²+2Y²+3X+3Y=1
已知3x²+xy-2y²=0(x≠0,y≠0),求x/y-y/x-x²+y²/x
计算:(1).(-2xy²)*(3x²y)²
已知x/y=3,求x²+2xy-3y²/x²-xy+y³的值
已知(x+2)²+|x+y+5|=0,求3x²y+{-2x²y-[-2xy+(x²