X²+10X+21=0
2(x²-7x)²-21(x²-7x)+10=0
1/x+1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...1/(x+9)(x+10)=0
(2x-2)(x-1)=0 x(x-5)=5x-10
已知x>0,则函数f(x)=(2x^2+7x+10)/x
x三次方+3x²-10x=0
用C语言编写程序,用牛顿迭代法求高次方程f(x)=5*x*x*x*x*x-8*x*x*x+10*x*x-7x+25=0的
1、x^2+10x+21=0
咋解咋解x²+10x+21=0
若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
已知x2+x-1=0,求x(1−21−x)÷(x+1)−x(x
已知函数f(x){x+1,x≤0 -2x,x>0,若f(x)=10则
用公式法解下列方程:(1)x-10x+21=0 (2)x-7x+11=0 (3)x-3x-1=0 (4)-5x=2x-1