作业帮 > 数学 > 作业

计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)

来源：学生作业帮 编辑：搜搜考试网作业帮 分类：数学作业 时间：2024/07/26 09:23:17
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)] /(x+1)/(x-3)
=[(x-2)/(x-3)+(x+2)/(x-3)] /(x+1)/(x-3)
=2x/(x-3)/(x+1)/(x-3)
=2x/(x+1)
x/x-3-5x/x^2-x-6计算 计算（x*x+4x+5）/（x+2）-（x*x+6x+10）/（x+3）+1 计算：（x+1)(x-2)(x-3)(x-6) 如何计算 (x+1)(x+2)(x+3)(x+4) 计算(X-1)(X-2)(X-3)(X-4) |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 计算：(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2) x^2+x-6分之x^2+3x-x^2-4分之x+2计算 计算x^2-5x+6/x^2-1/x^2+x/x-3 计算：(x-1)(x^2-4X+3)-x(x^2-5X+2)有过程 计算:(x+2)/(x^2 - x - 6) + 2x/(x^2 - 3x) - x/(x^2 - 6x + 9) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4