来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/07/26 01:47:30
运算放大器与受控源问题
![](http://img.wesiedu.com/upload/0/44/04448b0ce86a3cd916a4e5f0c61e9389.jpg)
如图,求转移电阻和转移电导
设电流并编号,见图
![](http://img.wesiedu.com/upload/3/84/384a56e75ce65b9f5531db4d83b02d21.jpg)
分析计算如下
i1=i=i3+i2
R1i1+R2i2=0
i2=-(R1/R2)i1
i3=i1-i2=(1+R1/R2)i1
u2=-R1i1-R3i3=-R1i1-R3(1+R1/R2)i1=-R1i-R3(1+R1/R2)i
u2=-[R1+R3(1+R1/R2)]i
转移电阻-[R1+R3(1+R1/R2)]
转移电导-1/[R1+R3(1+R1/R2)]