帮帮化简sin^4x-cos^4x
化简下面的三角函数f(x)=sin^2x+2√3sin(x+∏/4)cos(x-∏/4)-cos^2-√3
化简求值:sin(π/4-3x)*cos(π/3-3x)-cos(π/6+3x)*sin(π/4+3x)
根号下(sin""x+4cos"x)-根号下(cos""x+4sin"x)=?
证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4
用cos x表示sin^4 x -sin^2 x +cos^2 x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/2) 化简为sin的形式
三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2
d/dx sin^8(cos(4x))
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x