对任意整数x,y函数y=f(x)满足:f(x-y)=f(x)-f(y)-xy-1,若f(1)=1,则f(-8)=多少
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对任意整数x,y函数y=f(x)满足:f(x-y)=f(x)-f(y)-xy-1,若f(1)=1,则f(-8)=多少
![对任意整数x,y函数y=f(x)满足:f(x-y)=f(x)-f(y)-xy-1,若f(1)=1,则f(-8)=多少](/uploads/image/z/19078430-14-0.jpg?t=%E5%AF%B9%E4%BB%BB%E6%84%8F%E6%95%B4%E6%95%B0x%2Cy%E5%87%BD%E6%95%B0y%3Df%EF%BC%88x%EF%BC%89%E6%BB%A1%E8%B6%B3%3Af%EF%BC%88x-y%EF%BC%89%3Df%EF%BC%88x%EF%BC%89-f%EF%BC%88y%EF%BC%89-xy-1%2C%E8%8B%A5f%EF%BC%881%EF%BC%89%3D1%2C%E5%88%99f%EF%BC%88-8%EF%BC%89%3D%E5%A4%9A%E5%B0%91)
f(x-y)=f(x)-f(y)-xy-1
f(0)=f(1-1)=f(1)-f(1)-1-1=-2
f(-1)=f(0-1)=f(0)-f(1)-0-1=-4
f(-2)=f(-1-1)=f(-1)-f(1)+1-1=-5
f(-3)=f(-2-1)=f(-2)-f(1)+2-1=-5
f(-4)=f(-3-1)=f(-3)-f(1)+3-1=-4
f(-5)=f(-4-1)=f(-4)-f(1)+4-1=-2
f(-6)=f(-5-1)=f(-5)-f(1)+5-1=1
f(-7)=f(-6-1)=f(-6)-f(1)+6-1=5
f(-8)=f(-7-1)=f(-7)-f(1)+7-1=12
f(0)=f(1-1)=f(1)-f(1)-1-1=-2
f(-1)=f(0-1)=f(0)-f(1)-0-1=-4
f(-2)=f(-1-1)=f(-1)-f(1)+1-1=-5
f(-3)=f(-2-1)=f(-2)-f(1)+2-1=-5
f(-4)=f(-3-1)=f(-3)-f(1)+3-1=-4
f(-5)=f(-4-1)=f(-4)-f(1)+4-1=-2
f(-6)=f(-5-1)=f(-5)-f(1)+5-1=1
f(-7)=f(-6-1)=f(-6)-f(1)+6-1=5
f(-8)=f(-7-1)=f(-7)-f(1)+7-1=12
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