System.out.printf(String.format("%%2d | %%%dd …%%d\n",n) ) 请

printf("%2d"'--n) printf("%2d,\n",k) char x[]="string"; x[0]=0;x[1]='\0';x[2]='0'; printf("%d%d\n printf("%s%s%s%d%d%d\n",printf("\n"); int i=9999;printf("%d\n",printf("%d",printf("%d",printf("%d" 求sum=d+dd+ddd+……+dd...d(n个d),其中d为1-9的数字. 请大侠解释一下CString str;str.Format(L"\n%d!=%d",n,s);这两句代码的含义,以及CS main() { int m=12, n=34; printf("%d%d",m++,++n) printf("%d%d 关于C语言 printf("%d\n",printf("%d",printf("%d",i))); main( ) 　{ int n; ( n=6*4,n+6),n*2; printf(“n=%d\n”,n); } 　此 printf("k=% %d\n",结果呢? main() { int n=4; while(n--) printf("%d",--n); }