5x+10y=14
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
探究方程组{2x+5y=7 4x+10y=14{4x+10y=10 2x+5y=7{2x+5y=7 4x+6y=10
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
若实数X,Y满足方程5X²-12XY+10Y²-6X-14Y+13=0,则X=?Y=?
(7x-10y)-(-10y-5x)=?
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y
解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66
解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66
10/x+y+3/x-y=-5 15/x+y-2/x-y=-1(用换元法解此方程组)
3x+2y=6 ,5x+6y=10那么x+y=?