(x²+y²)²-4x²y² (x+y)²-4(x+y-1)
x(x-y)-y(y-x)+(x-y)²因式分解
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
(x-2y)²+(2x-4y)(x+y)+(x+y)²
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
因式分解x²(x-2y)+y²(2y-x)
(2x+y)²-y(y+4x)-8x等于?
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
x²+y²-4x+6y+13=0,求(3x+y)²-3(3x+y)(x+y)-(x-3y)
(x+y)²+4(x+y)-5