(log32+log23)^2-log32/log23-log23/log32
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(log32+log23)^2-log32/log23-log23/log32
log32就是3是底数,2是真数
log32就是3是底数,2是真数
![(log32+log23)^2-log32/log23-log23/log32](/uploads/image/z/19497542-14-2.jpg?t=%28log32%2Blog23%29%5E2-log32%2Flog23-log23%2Flog32)
[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2)
=[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2)
=[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2
=2/[log2(3)*log3(2)]
=2
再问: 为什么倒数第二步是2/啊
再答: 2是平方
=[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2)
=[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2
=2/[log2(3)*log3(2)]
=2
再问: 为什么倒数第二步是2/啊
再答: 2是平方
(log23+log89)(log34+log98+log32)=______.
运用对数的换底公式化简log23×log34×log45×log52:;(log43+log83)(log32+log9
设a=log32,b=log52,c=log23,则a,b,c的大小关系为______.
(log43+log83)(log32+log92)
(lg5)^2+2lg2-(lg2)^2+log23乘log34等于?
(log43+log83)(log32+log92)=
log89除以log23的值为
log32乘以[根号(2+根号三)-根号(2-根号三)] 32是底数
a=log32 b=in2 c=5-1/2 比大小(有具体方法
log32×log89过程 3和8是底数,2和9是真数
高一简单对数题.急log23*log35*log58 这个2是a , 3是n
函数y=log23(3x-2)的定义域为 ___ .