数列{an}满足1/2a1+1/2^2a2+1/2^3a3……1/2^nan=2n+5.求通项
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数列{an}满足1/2a1+1/2^2a2+1/2^3a3……1/2^nan=2n+5.求通项
![数列{an}满足1/2a1+1/2^2a2+1/2^3a3……1/2^nan=2n+5.求通项](/uploads/image/z/19527725-29-5.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B31%2F2a1%2B1%2F2%5E2a2%2B1%2F2%5E3a3%E2%80%A6%E2%80%A61%2F2%5Enan%3D2n%2B5.%E6%B1%82%E9%80%9A%E9%A1%B9)
![](http://img.wesiedu.com/upload/8/e8/8e80a54c0213b81df40bf5b09163676e.jpg)
再问: 还想问一道,已知a1=sint平方,an+1=4an(1-an),求a2,a3和通项
再答: a2=(sin2t)平方
a3=(sin4t)平方
猜想得到:
an=(sin2的n-1次方t)平方
再问: a2,a3怎么求
再答: 代进去,用倍角公式
再问: 能不能举个例子阿,不太好意思我算了就是不对
再答:
![](http://img.wesiedu.com/upload/7/97/7979e8fb8a937759a9cc62fa76319ba8.jpg)
再问: 太谢谢了
再问: 还有一个小问,有多少个不同的t使得a2014=0
再答: t有范围吗,没有的话,就是无穷个
再问: 【0,派/2】
再答:
![](http://img.wesiedu.com/upload/d/88/d88f1cf00f7e0f9e2df18b2f30c0a96b.jpg)
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