搜搜考试网sin(x+y)sin(x-y)=m,则(cosx)^2-(cosy)^2的值为
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sin(x+y)sin(x-y)=m,则(cosx)^2-(cosy)^2的值为
求具体过程,谢谢!
求具体过程,谢谢!
sin(x+y)*sin(x-y)=m
(sinx*cosy+siny*cosx)*(sinx*cosy-siny*cosx)=m
(sinx*cosy)^2-(siny*cosx)^2=m
sin^2(x)*cos^2(y)-sin^2(y)*cos^2(x)=m
sin^2(x)*cos^2(y)-[1-cos^2(y)]*cos^2(x)=m
sin^2(x)*cos^2(y)-cos^2(x)+cos^2(y)*cos^2(x)=m
[sin^2(x)+cos^2(x)]*cos^2(y)-cos^2(x)=m
cos^2(y)-cos^2(x)=m
则(cosx)^2-(cosy)^2=-[cos^2(y)-cos^2(x)]
=-m
(sinx*cosy+siny*cosx)*(sinx*cosy-siny*cosx)=m
(sinx*cosy)^2-(siny*cosx)^2=m
sin^2(x)*cos^2(y)-sin^2(y)*cos^2(x)=m
sin^2(x)*cos^2(y)-[1-cos^2(y)]*cos^2(x)=m
sin^2(x)*cos^2(y)-cos^2(x)+cos^2(y)*cos^2(x)=m
[sin^2(x)+cos^2(x)]*cos^2(y)-cos^2(x)=m
cos^2(y)-cos^2(x)=m
则(cosx)^2-(cosy)^2=-[cos^2(y)-cos^2(x)]
=-m
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