求值cosπ/5cos2π/5cos4π/5cos8π/5
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求值cosπ/5cos2π/5cos4π/5cos8π/5
![求值cosπ/5cos2π/5cos4π/5cos8π/5](/uploads/image/z/19760407-7-7.jpg?t=%E6%B1%82%E5%80%BCcos%CF%80%2F5cos2%CF%80%2F5cos4%CF%80%2F5cos8%CF%80%2F5)
利用正弦二倍角公式
cosπ/5cos2π/5cos4π/5cos8π/5
=2sinπ/5cosπ/5cos2π/5cos4π/5cos8π/5/(2sinπ/5)
=sin2π/5cos2π/5cos4π/5cos8π/5/(2sinπ/5)
=2sin2π/5cos2π/5cos4π/5cos8π/5/(4sinπ/5)
=sin4π/5cos4π/5cos8π/5/(4sinπ/5)
=2sin4π/5cos4π/5cos8π/5/(8sinπ/5)
=sin8π/5cos8π/5/(8sinπ/5)
=2sin8π/5cos8π/5/(16sinπ/5)
=sin16π/5/(16sinπ/5)
=sin(3π+π/5)/(16sinπ/5)
=-sinπ/5/(16sinπ/5)
=-1/16
cosπ/5cos2π/5cos4π/5cos8π/5
=2sinπ/5cosπ/5cos2π/5cos4π/5cos8π/5/(2sinπ/5)
=sin2π/5cos2π/5cos4π/5cos8π/5/(2sinπ/5)
=2sin2π/5cos2π/5cos4π/5cos8π/5/(4sinπ/5)
=sin4π/5cos4π/5cos8π/5/(4sinπ/5)
=2sin4π/5cos4π/5cos8π/5/(8sinπ/5)
=sin8π/5cos8π/5/(8sinπ/5)
=2sin8π/5cos8π/5/(16sinπ/5)
=sin16π/5/(16sinπ/5)
=sin(3π+π/5)/(16sinπ/5)
=-sinπ/5/(16sinπ/5)
=-1/16
cos π/15 * cos 2π/15 * cos4π/15 * cos8π/15
COSπ/5乘以COS2π/5
求COSπ/5*COS2π/5
求值:cos2π7
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cosπ/5·cos2π/5等于多少?
(cosπ/5)(cos2π/5)的值等于
cosπ/5 乘以cos2π/5等于多少
已知α∈(π/2,π),且sinα=3/5,则sin^2α/2+(sin4αcos2α)/(1+cos4α)的值为多
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