各位数学精英帮帮忙…
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/09 21:12:48
各位数学精英帮帮忙…
![各位数学精英帮帮忙…](/uploads/image/z/19832162-50-2.jpg?t=%E5%90%84%E4%BD%8D%E6%95%B0%E5%AD%A6%E7%B2%BE%E8%8B%B1%E5%B8%AE%E5%B8%AE%E5%BF%99%E2%80%A6%26nbsp%3B)
1、2(3n-2)(2n+3)/n(2n+3)(2n-3)x3(2n-3)(6n-5)/2(3n+2)(6n-5)=3(3n-2)/n(3n+2)
再问: 谢谢您
再问:![](http://img.wesiedu.com/upload/1/b7/1b73df8fa755267888b5c910b0e44423.jpg)
再问: 还有一题 麻烦啦
再答: 这题第三个分式的分母因式分解为(2y-3)(y-2) 整体分母都变为(2y-3)(y-2), 全式为[(y+2)(y-2)+(y+3)(2y-3)-(y2+2y-7)]/(2y-3)(y-2) =(y²-4+2y²+3y-9-y²-2y+7)/(2y-3)(y-2) =(2y²+y-6)/(2y-3)(y-2) =(2y-3)(y+2)/(2y-3)(y-2) =(y+2)/(y-2)
再问: 谢谢您
再问:
![](http://img.wesiedu.com/upload/1/b7/1b73df8fa755267888b5c910b0e44423.jpg)
再问: 还有一题 麻烦啦
再答: 这题第三个分式的分母因式分解为(2y-3)(y-2) 整体分母都变为(2y-3)(y-2), 全式为[(y+2)(y-2)+(y+3)(2y-3)-(y2+2y-7)]/(2y-3)(y-2) =(y²-4+2y²+3y-9-y²-2y+7)/(2y-3)(y-2) =(2y²+y-6)/(2y-3)(y-2) =(2y-3)(y+2)/(2y-3)(y-2) =(y+2)/(y-2)