tan(-13pi/4)与tan(-17pi/5)比较大小
正切函数比大小!tan(-13/4π)与tan(-17/5π)
tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ
tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,
matlab求解方程.f=x*sin(y)+((pi*12/4+(60-x)*tan(pi/9))+48*y)*tan(
化简三角函数[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-p
怎么用matlab计算出pi/2=x+arccos(tan(pi/4-x/2)中未知数x的值
如何比较e^pi和pi^e的大小?
化简间sin(a-2pi)cos(a+pi)tan(a-99pi)cos(pi-a)sin(3pi-a)sin(-a-p
tana=2求sin(pi-a)cos(2pi-a)sin(-a+3pi/2)/tan(-a-pi)sin(-pi-a)
f(a)=sin(pi-a)cos(2pi-a)tan(-a+3pi/2)/cos(-pi-a) 求 f(-31pi/3
tan(5+a)=-2,且cos>0,则sin(-pi+a)=?/
lim(n->无穷) (tan(pi/4 + 1/n)) ^n的极限 为什么是 e^2