√m^2n^4+m^4n^2(m≥0,n≥0)化简
证明(m+n)²/2+(m+n)/4≥(m√n)+(n√m)
(m-n)2(n-m)3(n-m)4化简
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
要证 [(m+n)/2]^(m+n)≥m^n×n^m 只需证[√(mn)]^(m+n))≥m^n×n^m 逻辑对吗? 自
因式分解4m^2(m-n)+4n(n-m)
[(m-n)^2*(m-n)^3]^2/(m-n)^4
m^+4m+n^-2n+5=0,求4m+5n=?
|m-n+2|+2m+n+4=0 m=?n=?
m^2+4m+n^2-6n+13=0,则m+n=
若m^2+n^2-6n+4m+13=0则m-n=?
m平方+2M+N平方-4N+5=0,求M,N
如果m-3n+4=0 求(m-3n)^2+7m^3-3(2m^3n-m^2n-1)+3(m^3+2m^3n-m^2n+n