(2013•扬州)(1)计算:(12)−2−2sin60°+12;
(2012•海门市一模)(1)计算:−12012+(12)−2−(tan62°+2π)0+|27−8sin60°|,
(2014•响水县二模)(1)计算:(12)2-2sin60°+12; &
(2013•历城区二模)(1)计算:−22−12+|1−4sin60°|+(π−23)0;
计算:2sin60°+/-3/-根号12-(3分之1)负一
计算:√12+|-2|-4sin60º+(√3+1)º
(2010•天桥区二模)(1)计算:13+1+(3-π)0-sin60°
sin60°=根号3/2 如何计算出来
计算下列各式 sin30°*cos30°-(√2)/2 sin45°-cos60°*sin60°
(2011•江苏模拟)(1)计算:|1-3|-sin60°+(-25)0-124.
数学计算题 题目如下(-3)²+根号12-|1-4sin60°| 竖线是绝对值 其实我主要是绝对值计算搞不清楚
计算(-根号下2)的0次幂-(3分之1)的-1次幂-|-根号下3|+2sin60°
计算:sin60°-cos60°+2sin30°cos30° 根号三sin60°-根号2cos45°+根号8的立方