10B

(a-b)^10/(b-a)^4/(b-a)^8 请问：=SUMPRODUCT(($B$2:$B$10>B2)/COUNTIF($B$2:$B$10,$B$2:$B$10 4a³b-10b³)+(3a²b²+10b³) a^2+b^2=100,a/10=b/(b+10)求解a,b printf("%d\n",i>5?10:100);b++;y=(a+b,a-b,a*b); 已知B有两种同位素,10B,和11B,B元素的相对原子质量为10.8, B b. (b, A=10 B=20 A=A+B B=A-B A=A-B Print"A=";A,"B=";B 宁海哪买10B,9B,8B,7B,6B,5B,4B,3B,2B,B,HB,F,H,2H,3H,4H,5H,6H,7H,8 设a>b>1,且loga(b)+log(b)a=10/3,求loga(b)-log(b)a