x-2y+z=9, 2x+y+3z=10, 3x+2y-4z=-3

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z, x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x/2=y/3=z/5 x+3y-z/x-3y+z (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=—— x/10 = y/8 =z/9 求x+2y+3z/y-5z