分解因式1. x^4+4 2. x^4+y^4+(x+y)^4 3. 4x^2y^2-x^4-y^4-z^4-2(x^2
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分解因式1. x^4+4 2. x^4+y^4+(x+y)^4 3. 4x^2y^2-x^4-y^4-z^4-2(x^2y^2-y^2z^2-z^2x*2) 速度啊啊
![分解因式1. x^4+4 2. x^4+y^4+(x+y)^4 3. 4x^2y^2-x^4-y^4-z^4-2(x^2](/uploads/image/z/4508436-12-6.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F1.+x%5E4%2B4+2.+x%5E4%2By%5E4%2B%28x%2By%29%5E4+3.+4x%5E2y%5E2-x%5E4-y%5E4-z%5E4-2%28x%5E2)
1.x^4+4
=x^4+4x^2+4-4x^2
=(x^2+2)^2-(2x)^2
=(x^2+2+2x)(x^2+2-2x)
2.x^4+y^4+(x+y)^4
=x^4+y^4+(x^2+y^2+2xy)^2
=(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2
=2[(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2]
=2(x^2+y^2+xy)^2
3.4x^2y^2-x^4-y^4-z^4-2(x^2y^2-y^2z^2+z^2x*2)
=-[x^4+y^4-2x^2y^2-2x^2y^2+z^4+2x^2y^2-2y^2z^2+2z^2x*2]
=-[(x^2-y^2)^2+z^4+2z^2(x^2-y^2)]
=-(x^2-y^2+z^2)^2
再问: 第2的答案请详细点 我水平较低... 第三的答案是(x+y+z)(x+y-z)(x-y+z)(y+z-x) 你再试试
再答: 2. x^4+y^4+(x+y)^4 =x^4+y^4+【(x^2+y^2)+2xy】^2 =(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 =2(x^2+y^2)^2+2x^2y^2+4xy(x^2+y^2) =2[(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2] =2(x^2+y^2+xy)^2 3,4x^2y^2-x^4-y^4-z^4-2(x^2y^2-y^2z^2-z^2x*2) =-[(x²-y²)²-2x²y²+z^4+2x²y²-2y²z²-2z²x²] =-[(x²-y²)²+z^4-y²z²-z²x²+2xyz²-2xyz²-y²z²-z²x²] =-[(x²-y²)²+z^4-z²(x-y)²-z²(x+y)²] =-{(x+y)²(x-y)²-z²[(x-y)²+(x+y)²]+z^4} =-[(x+y)²-z²][(x-y)²-z²] (x+y)²╲ -z² 十字相乘 =-(x+y+z)(x+y-z)(x-y+z)(x-y-z) (x-y)² ╱ -z²
再问: =(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 怎么来的?
再答: x^4+y^4 【(x^2+y^2)+2xy】^2 =x^4+y^4+2x^2y^2-2x^2y^2 =(x^2+y^2)^2-2x^2y^2 =(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 给你分开了!输入好麻烦的
=x^4+4x^2+4-4x^2
=(x^2+2)^2-(2x)^2
=(x^2+2+2x)(x^2+2-2x)
2.x^4+y^4+(x+y)^4
=x^4+y^4+(x^2+y^2+2xy)^2
=(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2
=2[(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2]
=2(x^2+y^2+xy)^2
3.4x^2y^2-x^4-y^4-z^4-2(x^2y^2-y^2z^2+z^2x*2)
=-[x^4+y^4-2x^2y^2-2x^2y^2+z^4+2x^2y^2-2y^2z^2+2z^2x*2]
=-[(x^2-y^2)^2+z^4+2z^2(x^2-y^2)]
=-(x^2-y^2+z^2)^2
再问: 第2的答案请详细点 我水平较低... 第三的答案是(x+y+z)(x+y-z)(x-y+z)(y+z-x) 你再试试
再答: 2. x^4+y^4+(x+y)^4 =x^4+y^4+【(x^2+y^2)+2xy】^2 =(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 =2(x^2+y^2)^2+2x^2y^2+4xy(x^2+y^2) =2[(x^2+y^2)^2+2xy(x^2+y^2)+(xy)^2] =2(x^2+y^2+xy)^2 3,4x^2y^2-x^4-y^4-z^4-2(x^2y^2-y^2z^2-z^2x*2) =-[(x²-y²)²-2x²y²+z^4+2x²y²-2y²z²-2z²x²] =-[(x²-y²)²+z^4-y²z²-z²x²+2xyz²-2xyz²-y²z²-z²x²] =-[(x²-y²)²+z^4-z²(x-y)²-z²(x+y)²] =-{(x+y)²(x-y)²-z²[(x-y)²+(x+y)²]+z^4} =-[(x+y)²-z²][(x-y)²-z²] (x+y)²╲ -z² 十字相乘 =-(x+y+z)(x+y-z)(x-y+z)(x-y-z) (x-y)² ╱ -z²
再问: =(x^2+y^2)^2-2x^2y^2+(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 怎么来的?
再答: x^4+y^4 【(x^2+y^2)+2xy】^2 =x^4+y^4+2x^2y^2-2x^2y^2 =(x^2+y^2)^2-2x^2y^2 =(x^2+y^2)^2+4xy(x^2+y^2)+4x^2y^2 给你分开了!输入好麻烦的
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