关于管理会计的计算题The cost driver for variable costs is "child-days"
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关于管理会计的计算题
The cost driver for variable costs is "child-days".One child-day is one day in day care for one child,and the variable cost is $10 per child-day.The facility is open from 6:00 am to 6:00 pm weekdays,and there are 22 weekdays in november 20x7.An average day has 8 children attending beth's corner.State law prohibits beth's corner from having more than 14 children,a limit it has never reached.Durham charges $30 per day per child,regardless of how long the child is at the facility.
Total fixed costs=$2300
Q:1.what is the break-even point for November in child-days?In revenue dollars?
2.Suppose attendance for November 20X7 is equal to the average,resulting in 22*8=176 child-days .What amount willDurham have left paying all her expenses?
请写清楚计算步骤,答得好的回复我会追加分数!
The cost driver for variable costs is "child-days".One child-day is one day in day care for one child,and the variable cost is $10 per child-day.The facility is open from 6:00 am to 6:00 pm weekdays,and there are 22 weekdays in november 20x7.An average day has 8 children attending beth's corner.State law prohibits beth's corner from having more than 14 children,a limit it has never reached.Durham charges $30 per day per child,regardless of how long the child is at the facility.
Total fixed costs=$2300
Q:1.what is the break-even point for November in child-days?In revenue dollars?
2.Suppose attendance for November 20X7 is equal to the average,resulting in 22*8=176 child-days .What amount willDurham have left paying all her expenses?
请写清楚计算步骤,答得好的回复我会追加分数!
1. Let N = number of units
Sales = Fixed expenses + Variable expenses + Net income
$1.00 N = $6,000 + $.80 N + 0
$.20 N = $6,000
N = 30,000 units
Let S = sales in dollars
S = $6,000 + .80 S + 0
.20 S = $6,000
S = $30,000
Sales = Fixed expenses + Variable expenses + Net income
$1.00 N = $6,000 + $.80 N + 0
$.20 N = $6,000
N = 30,000 units
Let S = sales in dollars
S = $6,000 + .80 S + 0
.20 S = $6,000
S = $30,000
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