(2x²-3x)²-5(2x²-3x)-6=0 3x/(x²-1)+x²
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(2x²-3x)²-5(2x²-3x)-6=0 3x/(x²-1)+x²-1/3x=5/2 用换元法解方程
![(2x²-3x)²-5(2x²-3x)-6=0 3x/(x²-1)+x²](/uploads/image/z/7545423-39-3.jpg?t=%282x%26%23178%3B-3x%29%26%23178%3B-5%282x%26%23178%3B-3x%29-6%3D0+3x%2F%EF%BC%88x%26%23178%3B-1%EF%BC%89%2Bx%26%23178)
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(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x
6x+(2x²-3x)-(x²-1)
f(x)=x²+3x|x-2|
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
代数式6x+2x²-3x+x²+1,其中x=-5
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①2(x+3)(x-3)=x²+(x-1)(x+1)+2x