2x+1/6-4x-1/8=1 x-1/0.5-x+2/0.3=2 3/4[3/4(12x+1/4)-8]=3/2x+1

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/08/17 23:22:56

2x+1/6-4x-1/8=1 x-1/0.5-x+2/0.3=2 3/4[3/4(12x+1/4)-8]=3/2x+1
怎么算呀?要过程哦.谢了.

(1)
2x+1/6-4x-1/8=1
2x - 4x + 1/24 = 1
-2x = 23/24
x = -23/48
若写成：
(2x+1)/6-(4x-1)/8=1
则方程两边都乘以24
(2x+1)*4 - (4x-1)*3 = 24
8x + 4 - 12x +3 = 24
-4x = 17
x = -17/4
(2)
x-1/0.5-x+2/0.3=2
因为左边x-x消去了未知数,方程无解.
若写成：
(x-1)/0.5-(x+2)/0.3=2
2x-2 - (10/3)x - 20/3 = 2
(-4/3)x = 32/3
x = -8
(3)
3/4[3/4(12x+1/4)-8]=3/2x+1
理解为：
(3/4) * [(3/4) * (12x+1/4) - 8] = (3/2)x + 1
(3/4) * [9x + 3/16 - 8] = (3/2)x + 1
(27/4)x + 9/64 - 6 = (3/2)x + 1
(21/4)x = 7 - 9/64
x = 439/112

x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550 y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), （1） x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8 (X+2)/(X+1)-(X+4)/(X+3)=(X+6)/(X+5)-(X+8)/(X+7) 解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3 |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x x(2x-4)+x(x-1)=2x(x-3)+8