5X-8Y=4 -3X Y=-0.5

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5X-8Y=4 -3X Y=-0.5
2xy-1/2(4xy-8x²y²)+2(3xy-5x²y²),其中x=3/2,

x=3/2,y=-2/3xy=3/2*(-2/3)=-12xy-1/2(4xy-8x²y²)+2(3xy-5x²y²)=2xy-2xy+4x²y

已知xy/x+y=2,则代数式3x-5y+8y/-x+3xy-y的值

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已知X+Y=6,XY=-4,求(5X-4Y-3XY)-(8X-Y+2XY)的值

(5X-4Y-3XY)-(8X-Y+2XY)=-(3X+3Y)-5XY=-3*6+4*5=2

已知x+y=5,xy=2,求5x+4y-3x-2y+xy的值

5x+4y-3x-2y+xy=2x+2y+xy=2(x+y)+xy因:x+y=5,xy=2所以原式=2X5+2=12

x*-2xy+3y*=9 4x*-5xy+6y*=30

Solution:x^2-2xy+3y^2=9(1)4x^2-5xy+6y^2=30(2)Eq(1)*5-Eq(2)*2,wehavex^2-y^2=5(3)Eq(2)-Eq(1),wegetx^2+

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

已知x+y=3,xy=1,求代数式5xy+4x+7y+6x-3xy-4xy+3y的值.

5xy+4x+7y+6x-3xy-4xy+3y=5xy-3xy-4xy+4x+6x+7y+3y=(5-3-4)xy+(4+6)x+(7+3)y=-2xy+10x+10y=-2xy+10(x+y)因为x

若1/x+1/y=5,求3x+4xy+3y/x+3xy+y的值

1/x+1/y=5两边乘以xy得y+x=5xy∴x+y=5xy3x+4xy+3y/x+3xy+y=[3(x+y)+4xy]/[(x+y)+3xy]=(15xy+4xy)/(5xy+3xy)=19xy/

已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=?

1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因

1、已知x+y=5,xy=3,求多项式2(x+3y-2xy)-(4x+8y-2xy)的值.

解2(x+3y-2xy)-(4x+8y-2xy)=2x+6y-4xy-4x-8y+8xy=-2x-2y+4xy=-2(x+y)+4xy=-2×5+4×3=12-10=24x²-3y²

已知X+Y=6,xy=3求代数式(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)的值

先把代数式(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)化简(5XY+4X+7Y)+(6X-3XY)-(4XY-3Y)=5XY+4X+7Y+6X-3XY-4XY+3Y=-2XY+10X+1

5xy平方-2x平方y+[3xy平方-(4xy-2x平方y-2x平方y)],其中x=-2,y=-1求值

5xy平方-2x平方y+[3xy平方-(4xy-2x平方y-2x平方y)]=5xy平方-2x平方y+[3xy平方-4xy+2x平方y+2x平方y)]=5xy平方-2x平方y+3xy平方-4xy+2x平

x-y=3,xy=5,求代数式(7xy+4x-7y)+(6x-3xy)-(3y+4xy)的值

(7xy+4x-7y)+(6x-3xy)-(3y+4xy)=7xy+4x-7y+6x-3xy-3y-4xy=10x-10y=10(x-y)=10*3=30

若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4=( )

=(x^4+x^3y)+(y^4+xy^3)+(4x^3y+4x^2y^2)+(4xy^3+4x^2y^2)+x^2y+xy^2=x^3(x+y)+y^3(x+y)+4x^2y(y+x)+4xy^2(

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

x+y=8,xy=-2,求(5xy+4x+7y)+(6x-3xy)-(4xy-3y)的值

(5xy+4x+7y)+(6x-3xy)-(4xy-3y)=5xy+4x+7y+6x-3xy-4xy+3y=(5xy-3xy-4xy)+(4x+6x)+(7y+3y)=-2xy+10x+10y=-2x

已知 x+y=3,xy=-2,求(3x-2y+8xy)-(x-4y-5xy)的值

(3x-2y+8xy)-(x-4y-5xy)=3x-2y+8xy-x+4y+5xy=2x+2y+13xy=2(x+y)+13xy=2×3+13×(-2)=-20

已知x+y=5,xy=2,求5x+4y-3y-2y+xy的值

5x+4y-3x-2y+xy=2x+2y+xy=2(x+y)+xy因:x+y=5,xy=2所以原式=2X5+2=12你抄错了应该是5x+4y-3x-2y+xy

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-