求z=yx^2-xy^2的偏导数

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求z=yx^2-xy^2的偏导数
解方程组xy+xz=8-x^2,yx+yz=12-y^2,zy+zx=-4-z^2

xy+xz=8-x²yx+yz=12-y²zy+zx=-4-z²x(x+y+z)=8y(x+y+z)=12z(x+y+z)=-4(x+y+z)²=8+12-4=

求方程(y^2+xy^2)dx+(x^2-yx^2)dy=0的通解

∵(y^2+xy^2)dx+(x^2-yx^2)dy=0==>y²(1+x)dx+x²(1-y)dy=0==>[(y-1)/y²]dy=[(1+x)/x²]dx

已知x-y=a,z-y=10,求x^2+y^2+z^2-xy-yx-zx的最小值

由于x-y=a,z-y=10得x-z=a-10并且由x²+y²+z²-xy-yx-zx=1/2[(x-y)²+(y-z)²+(z-x)²]=

实数x、y、z满足x=6-3yx+3y-2xy+2z

x=6-3y               &nbs

已知:y=1−8x+8x−1+12,则代数式xy+yx+2-xy+yx−2的值为(  )

∵1-8x≥0,8x-1≥0,∴x=18,y=12,∴代数式xy+yx+2-xy+yx−2=14+4+2-14+4−2=52-32=1.故选:B.

已知x+4y+3z=3x-2y-5z=0(xyz不等于0),求xy+yx+2xz/2x平方-3y平方+7z平方

x+4y+3z=0x=-4y-3z3x-2y-5z=03x=2y+5zx=(2y+5z)/3所以-4y-3z=(2y+5z)/3-12y-9z=2y+5z14y=-14zy=-z所以x=-4*(-z)

xy-3xy+2yx-yx

=xy-3xy+2xy-xy=-xy

已知3x2+xy-2y2=0,求(x+yx-y+4xyy

原式=[(x+y)2(x-y)(x+y)+-4xy(x-y)(x+y)]×(x+3y)(x-3y)(x+3y)(x-y)=x-3yx+y,由已知得(3x-2y)(x+y)=0,因为x+y≠0,所以3x

z=f(x^2-y^2,xy),求z关于y的偏导

你只要X看成是是常数求导就行了,答案就不给你了,自己动手丰衣足食

已知y=3xy+x,求代数式2x+3xy−2yx−2xy−y

因为y=3xy+x,所以x-y=-3xy,当x-y=-3xy时,2x+3xy−2yx−2xy−y=2(x−y)+3xy(x−y)−2xy=2(−3xy)+3xy−3xy−2xy=35.

求下列函数的偏导数 1)z=x^3*y^2 2)z=x^4+y^3 3)z=e^(xy)+yx^2 4)u=x^(z/y

1.z'x=3x²y²z'y=2x³y2.z'x=4x³z'y=3y³3.z'x=ye^(xy)+2xyz'y=xe^(xy)+x²4.u'

已知yx^2+2xy^3+3=-18 求dy/dx

两边对x求导得y'x^2+2xy+2y^3+4xy^2y'=0解出来y'就可以了再问:4xy^2y'为什么是4xy再答:搞错了,应该是6xy^2y'再问:yx^2+2xy^3+3=-18上点(1,-2

已知2x2-3xy+y2=0(xy≠0),则xy+yx的值是(  )

根据题意,2x2-3xy+y2=0,且xy≠0,故有(yx)2−3yx+2=0,即(yx−1)(yx−2)=0,即得yx=1或2,故xy=1或12,所以xy+yx=2或212.故选A.

3xy-3xy-xy+2yx

3xy-3xy-xy+2yx=-xy+2xy=xy

已知2x2-xy-3y2=0,求x−yx+y

2x2-xy-3y2=0,(2x-3y)(x+y)=0,解得:2x-3y=0或x+y=0(分母为0,舍去),解得:x=3y2,则x−yx+y=3y2−y3y2+y=y5y=15.

已知2的X次方等于5的Y次方等于10的Z次方,求证:XY=XZ+YX

XY=XZ+YX?那么也就是XY=X(Z+Y)咯,Y=Z+Y?无法证明的.题抄错啦~`

求方程dy/dx=(1+y^2)/(xy+yx^3)的解.

dy/dx=(1+y^2)/[xy(1+x^2)]y/(1+y^2)dy=dx/[x(1+x^2)]2y/(1+y^2)dy=2xdx[x^2(1+x^2)]d(y^2)/(1+y^2)=d(x^2)

已知xy满足x^2+y^2+4/5=2x+y 求代数式yx/x+y的值

你抄错题了吧X2+Y2+5/4=2X+Y移项,得(X-1)2+(Y-1/2)2=0X=1,Y=1/2

已知x:y:z=1:2:3,且xy+yx+xz=66,求2(x的平方)+12(y的平方)-9(z的平方)的值

-186;由x:y:z=1:2:3所以y=2xz=3x代入xy+xz+yz=66解出xyz再代入满意请采纳

代数式(xyz²+4yx-1)+(-3xy+z²xy-3)-(2xyz²+xy)的值

(xyz²+4yx-1)+(-3xy+z²xy-3)-(2xyz²+xy)=xyz²+4yx-1-3xy+z²xy-3-2xyz²-xy=-