x+2y+3z=12x+3y+z=23x+y+2z=3
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x+2y+3z=12x+3y+z=23x+y+2z=3
2x+y+3z=383x+2y+4z=564x+y+5z=66
x+y−2z=52x−y+z=42x+y−3z=10
若x+2y-4z=0 3x+y-z=0 求x:y:z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
十万火急!4x-9z=17 3x+y+15z=18 x+2y+3z=
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x/2=y/3=z/5 x+3y-z/x-3y+z
已知x−y+z=0x+2y−3z=0
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
解方程组:3x−y+2z=32x+y−3z=11x+y+z=12