已知︴ab-2︴与︴b-1︴互为相反数,试求代数式1∕ab+1/(a+1)(b+1)+1/(a+2)(b-2)+…+1/
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已知︴ab-2︴与︴b-1︴互为相反数,试求代数式1∕ab+1/(a+1)(b+1)+1/(a+2)(b-2)+…+1/(a+2008)(b+2008)的
值
值
![已知︴ab-2︴与︴b-1︴互为相反数,试求代数式1∕ab+1/(a+1)(b+1)+1/(a+2)(b-2)+…+1/](/uploads/image/z/1265778-18-8.jpg?t=%E5%B7%B2%E7%9F%A5%EF%B8%B4ab-2%EF%B8%B4%E4%B8%8E%EF%B8%B4b-1%EF%B8%B4%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E8%AF%95%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F1%E2%88%95ab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b-2%29%2B%E2%80%A6%2B1%2F)
因为|(ab-2)|与|(a-1)|互为相反数,所以得
|(ab-2)|+|(a-1)| = 0
所以 ab-2=0 a-1=0
解得a=2 a=1
所以 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2006)(b+2006)
=1/(1*2)+1/(2*3)+.+1/(2007*2008)
=1-1/2+1/2-1/3+.+1/2007-1/2008
=1-1/2008
=2007/2008
|(ab-2)|+|(a-1)| = 0
所以 ab-2=0 a-1=0
解得a=2 a=1
所以 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2006)(b+2006)
=1/(1*2)+1/(2*3)+.+1/(2007*2008)
=1-1/2+1/2-1/3+.+1/2007-1/2008
=1-1/2008
=2007/2008
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