f(x)=cos²(π/6)+sinπ/6cosπ/6
f(x)=cos²(π/6)+sinπ/6cosπ/6
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos²x,(1)求f(x)的最小正周
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
设函数f(x)=2+sin(3x+π/12)cos(x+π/6)+cos(3x+π/12)sin(x+π/6)
已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x).
函数f(x)=sin(x/2+π/6)cos(x/2-π/6)的最小值?
求函数f(x)=sin(π/3+4x)+cos(4x-π/6
f(x)=2SIN^2(x+π\4)-cos(2x+π\6) 化简 谢
已知函数f(x)=cos^2(x-π/6)-sin^2x化简