(1+2/3+2+3/4+3+4/5+……+97+98/99+98+99/100)/(3+1/3+5+2/4+7+3/5
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/07/16 08:16:00
(1+2/3+2+3/4+3+4/5+……+97+98/99+98+99/100)/(3+1/3+5+2/4+7+3/5+……+195+97/99+197+98/100)=()
![(1+2/3+2+3/4+3+4/5+……+97+98/99+98+99/100)/(3+1/3+5+2/4+7+3/5](/uploads/image/z/1383094-46-4.jpg?t=%281%2B2%2F3%2B2%2B3%2F4%2B3%2B4%2F5%2B%E2%80%A6%E2%80%A6%2B97%2B98%2F99%2B98%2B99%2F100%EF%BC%89%2F%EF%BC%883%2B1%2F3%2B5%2B2%2F4%2B7%2B3%2F5)
(1+2/3+2+3/4+3+4/5+……+97+98/99+98+99/100)/(3+1/3+5+2/4+7+3/5+……+195+97/99+197+98/100)
=[(1+2+3+……+98)+(2/3+3/4+4/5+……+99/100)]/[(3+5+……+197)+(1/3+2/4+……+98/100)]
=[99×49+98-(1/3+1/4+……+1/100)]/[100×98+98-2×(1/3+1/4+……+1/100)]
=[101×49-(1/3+1/4+……+1/100)]/[101×98-2×(1/3+1/4+……+1/100)]
=1/2
=[(1+2+3+……+98)+(2/3+3/4+4/5+……+99/100)]/[(3+5+……+197)+(1/3+2/4+……+98/100)]
=[99×49+98-(1/3+1/4+……+1/100)]/[100×98+98-2×(1/3+1/4+……+1/100)]
=[101×49-(1/3+1/4+……+1/100)]/[101×98-2×(1/3+1/4+……+1/100)]
=1/2
(1+2/3+2+3/4+3+4/5+……+97+98/99+98+99/100)/(3+1/3+5+2/4+7+3/5
解1+2-3+4+5-6+7+8-9……+97+98-99+100
计算:1+2-3+4+5-6+7+8-9+……+97+98-99+100
1-2+3-4+5-6+7-……+97-98+99-100+101怎么算
1+2-3-4+5+6-7-8+……+97+98-99-100怎么做?
1×3+2×4+3×5……+97×99+98×100=
2×2/1×3+4×4/3×5+6×6/5×7+……+98×98/97×99+100×100/99×101
1-2+3-4+5-6+7…+97-98+99-100
1-2-3+4+5-6-7+8+…+97-98-99+100.
1+2+3+4+5+……+95+96+97+98+99+100=?
1+2+3+4+5+……+97+98+99+100=等于多少?
1+2-3+4-5+6……-97+98-99+100=?