根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值:(1)x=2,y=3; (2)x
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根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值:(1)x=2,y=3; (2)x
、根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值.
(1)、x=2,y=3,(2)、x= -2,y= -4
、根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值.
(1)、x=2,y=3,(2)、x= -2,y= -4
![根据下列各组x、y的值,分别求出代数式x2+2xy+y2与x2-2xy+y2的值:(1)x=2,y=3; (2)x](/uploads/image/z/14914724-68-4.jpg?t=%E6%A0%B9%E6%8D%AE%E4%B8%8B%E5%88%97%E5%90%84%E7%BB%84x%E3%80%81y%E7%9A%84%E5%80%BC%2C%E5%88%86%E5%88%AB%E6%B1%82%E5%87%BA%E4%BB%A3%E6%95%B0%E5%BC%8Fx2%2B2xy%2By2%E4%B8%8Ex2-2xy%2By2%E7%9A%84%E5%80%BC%3A%281%29x%3D2%2Cy%3D3%3B+%282%29x)
(1)x2+2xy+y2=2*2+2*2*3+2*3=20
(2)x2+2xy+y2=-2*2+2*-2*-4+2*-4=4
(1)x2-2xy+y2=2*2-2*2*3+2*3=-2
(2)x2-2xy+y2=-2*2-2*-2*-4+2*-4=-28
(2)x2+2xy+y2=-2*2+2*-2*-4+2*-4=4
(1)x2-2xy+y2=2*2-2*2*3+2*3=-2
(2)x2-2xy+y2=-2*2-2*-2*-4+2*-4=-28
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