函数式子化简1-(sin^6∝+cos^6∝)原式=1-(sin^2∝+cos^2∝)(sin^4∝-sin^2∝*co
已知tan∝=2/3,求值:(1)(cos∝-sin∝/cos∝+sin∝)+(cos∝+sin
求证:sin^2/(sin-cos) - (sin+cos)/(tan^2 -1) =sin+cos
若sinα/√(1-cos^2 α)+√(1-sin^2 α)/cosα=0,则式子cos(sinα)的符号?sin(c
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
若sinθ+sin^2θ=1,则cos^2θ+cos^4θ+cos^6θ
求证:(1+cosθ+cosθ/2) /(sinθ+sinθ/2)=sinθ/1-cosθ
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos
若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a
求证:(cosβ/(1+sinβ))-(sinβ/(1+cosβ))=(2cosβ-2sinβ)/(1+sinβ+cos
求证(1+sinθ+cosθ)/(1+sinθ-cosθ)+(1-cosθ+sinθ)/(1+cosθ+sinθ)=2/
若tanα=根号下2 求1)(sinα+cosα)/(cosα-sinα) 2)2sin^α-sinαcosα+cos^
若tanα=根号2,求值(1)cosα+sinα/cosα-sinα;(2)2sin平方α-sinαcosα+cos平方