(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/07/16 18:43:11
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
![(1-sin^6a-cos^6a)/(sin^2a-sin^4a)](/uploads/image/z/4034341-37-1.jpg?t=%281-sin%5E6a-cos%5E6a%29%2F%28sin%5E2a-sin%5E4a%29)
分子=1-sin^6a-cos^6a
=1-(sin^6a+cos^6a)
=1-(sin²a+cos²a)(sin^4 a-sin^acos6a+cos^4 a)
=1-(sin^4 a-sin^acos^a+cos^4 a)
=1-〔(sin²a+cos²a)²-3sin^acos^a〕
=1-(1-3sin²acos²a)
=3sin²acos²a
分母=(sina+sin²a)(sina-sin²a)
=sina(1+sina)sina(1-sina)
=sin²a(1-sin²a)
=3sin²acos²a
分子/分母=(3sin²acos²a)/(sin²acos²a)=3
=1-(sin^6a+cos^6a)
=1-(sin²a+cos²a)(sin^4 a-sin^acos6a+cos^4 a)
=1-(sin^4 a-sin^acos^a+cos^4 a)
=1-〔(sin²a+cos²a)²-3sin^acos^a〕
=1-(1-3sin²acos²a)
=3sin²acos²a
分母=(sina+sin²a)(sina-sin²a)
=sina(1+sina)sina(1-sina)
=sin²a(1-sin²a)
=3sin²acos²a
分子/分母=(3sin²acos²a)/(sin²acos²a)=3
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
求值:1-sin^6a-cos^6a/1-sin^4a-cos^4a
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
(1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)
(1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=?
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简Sin A + Sin 2A / 1+cos A +
已知(4sin a-2cos a)/(5cos a +3sin a)=6/11,求cos^4 a-sin^4 a
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
已知cos^2A+cosA=1,则sin^6A+sin^2A=?
若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a