设数列{an} 满足a1=0,an+an+1=2,则a2011的值为( )
已知数列{an}中,a1=2,an*a(n+1)=-1,则a2011的值为
数列{an}满足a1=3/2,an+1=an^2-an+1,则1/a1+1/a2+...+1/a2010+1/a2011
1.已知数列{an}a1=-2,an+1=(1+an)/(1-an),则a2011=
已知数列{an}满足a1=1,an+1=2an/(an+2)(n∈N+),则数列{an}的通项公式为
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
已知数列{an}满足a1=1,an+1=2an+1 1)求证:数列{an+1}为等比数列; 2) 求{an}的通项an
已知数列an中 a1=3 a2=6 an+2=an+1-an(n+1 和n加2 是下标) 则a2011=
已知:数列{an}满足a1=16,an+1-an=2n,则ann的最小值为( )
已知数列{an} 满足a1=33,an+1-an=2n,则ann的最小值为( )
【急!】设{an}是由非负整数组成的数列,满足a1+0,a2=3,(an+1)( an )=(an-1)( an-2+2
设数列{an}满足a1=0,4an+1=4an+2根号(4an+1)+1,令bn=根号(4an+1)
设b>0,数列an满足a1=b,an=nban-1/an-1+n-1(n≥2)求数列an通向公式.