(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)
1.(1+1/2)[1+(1/2)^2][1+(1/2)^4][1+(1/2)^8]+(1/2)^15
(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1=
请用平方差公式运算.①(1+1/2)(1+1/2²)(1+1/2^4)(1+1/2^8)+1/2^15=?②(
(1-1/2^2)(1-1/3^2)(1-1/4^2)(1-1/5^2)(1-1/6^2)(1\1/7^2)(1-1/8
1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =()
1/2,1/4,
【数学】算一算,找规律.1/2+1/4+1/8= 1/2+1/4+1/8+1/16= 1/2+1/4+1/8+1/16+
(1+1/2)(1+1/2的2次方)(1+1/2的4次方)(1+1/2的8次方)+1/2的15次方.
用平方差公式(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15