(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:数学作业 时间:2024/08/18 03:38:43
(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程
![(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程](/uploads/image/z/16217350-70-0.jpg?t=%28x-1%29%28x-3%29%28x-4%29%28x-12%29%2B5x%5E2%3D0%E8%A7%A3%E6%96%B9%E7%A8%8B)
(x-1)(x-3)(x-4)(x-12)+5x^2=0
(x-1)(x-12)(x-3)(x-4)+5x^2=0
(x^2-13x+12)(x^2-7x+12)+5x^2=0
[(x^2-10x+12)-3x][(x^2-10x+12)+3x]+5x^2=0
(x^2-10x+12)^2-9x^2+5x^2=0
(x^2-10x+12)^2-4x^2=0
[(x^2-10x+12)-2x][(x^2-10x+12)+2x]=0
(x^2-12x+12)(x^2-8x+12)=0
(x^2-12x+12)(x-2)(x-6)=0
x1=2
x2=6
x^2-12x+12=0
x^2-12x=-12
x^2-12x+36=36-12
(x-6)^2=24
x-6=±2√6
x3=6+2√6
x4=6-2√6
(x-1)(x-12)(x-3)(x-4)+5x^2=0
(x^2-13x+12)(x^2-7x+12)+5x^2=0
[(x^2-10x+12)-3x][(x^2-10x+12)+3x]+5x^2=0
(x^2-10x+12)^2-9x^2+5x^2=0
(x^2-10x+12)^2-4x^2=0
[(x^2-10x+12)-2x][(x^2-10x+12)+2x]=0
(x^2-12x+12)(x^2-8x+12)=0
(x^2-12x+12)(x-2)(x-6)=0
x1=2
x2=6
x^2-12x+12=0
x^2-12x=-12
x^2-12x+36=36-12
(x-6)^2=24
x-6=±2√6
x3=6+2√6
x4=6-2√6
解方程 x(2x-4)+3x(x-1)=5x(x-3)+8
解方程:(4/x-2)+(x-1/x-5x+6)+(2/3-x)=0
解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)
解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
方程(x-1/x-2)-(x-3/x-4)=(x-2/x-3)-(x-4/x-5)解为x=7/2,(1/x-7)-(1/
解分式方程:x-3/x-1-x-4/x-2=x-5/x-3-x-6
解方程:2/x^2+x+3/x^2-x-4/x^2-1=0
解方程:2x(x-1)-x(3x+2)=-x(x+2)-12
解方程 3x/x×x-1+x×x-1/3x=5/2
解方程1/(x+x﹚+1/(x+3x+2﹚+1/(x+5x+6﹚+1/(x+7x+12﹚=4/21得
解方程(x-2)/(x-3)-(x-3)/(x-4)=(x-5)/(x-6)-(x-6)/(x-7)