一道数学分式方程(x-4)/(x-3)-(x-6)/(x-5)=(x-8)/(x-7)-(x-10)/(x-9)
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一道数学分式方程
(x-4)/(x-3)-(x-6)/(x-5)=(x-8)/(x-7)-(x-10)/(x-9)
(x-4)/(x-3)-(x-6)/(x-5)=(x-8)/(x-7)-(x-10)/(x-9)
(x-3-1)/(x-3)-(x-5-1)/(x-5)=(x-7-1)/(x-7)-(x-9-1)/(x-9)
1-1/(x-3)-1+1/(x-5)=1-1/(x-7)-1+1/(x-9)
1/(x-7)+1/(x-5)=1/(x-3)+1/(x-9)
(x-5+x-7)/(x-7)(x-5)=(x-3+x-9)/(x-3)(x-9)
(2x-12)/(x^2-12x+35)=(2x-12)/(x^2-12x+27)
(2x-12)[1/(x^2-12x+35)-1/(x^2-12x+27)]=0
因为x^2-12x+35不等于x^2-12x+27
所以1/(x^2-12x+35)-1/(x^2-12x+27)不等于0
所以2x-12=0
x=6
经检验
x=6是方程的解
1-1/(x-3)-1+1/(x-5)=1-1/(x-7)-1+1/(x-9)
1/(x-7)+1/(x-5)=1/(x-3)+1/(x-9)
(x-5+x-7)/(x-7)(x-5)=(x-3+x-9)/(x-3)(x-9)
(2x-12)/(x^2-12x+35)=(2x-12)/(x^2-12x+27)
(2x-12)[1/(x^2-12x+35)-1/(x^2-12x+27)]=0
因为x^2-12x+35不等于x^2-12x+27
所以1/(x^2-12x+35)-1/(x^2-12x+27)不等于0
所以2x-12=0
x=6
经检验
x=6是方程的解
一道数学分式方程(x-4)/(x-3)-(x-6)/(x-5)=(x-8)/(x-7)-(x-10)/(x-9)
解分式方程 x-7/x-9+x-3/x-5=x-4/x-6+x-6/x-8
解分式方程:(x-4)/(x-5)+(x-8)/(x-9)=(x-7)/(x-8)+(x-5)/( x-6)
解分式方程(X-4)/(X-5)-(X-5)/(X-6)=(X-7)/(X-8)-(X-8)/(X-9)
分式方程 x-9分之x-7加上x-5分之x-3=x-6分之x-4加上x-8分之x-6
分式方程:x-7/x-9+x-3/x-5=x-4/x-6+x-6/x-8(要过程、检验)
解一道初一的分式方程(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的
分式方程【初二数学】x+5/x²-x + 6/1-x =3/x
分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8)
一道分式方程.X-2分之X-1减X-3分之X-2=X-5分之X-4减X-6分之X-5.