满足an+1-an=an-an-1 可以证明是等差数列么?
数列an满足:a1=1,a(n+1)=an/an +1 (1)证明1/an是等差数列.(2)数列an的通项公式
已知数列an满足:an+1-2an=2^n+1,且a1=2 (1)证明{an/2^n}是等差数列 (2)求数列an的
若数列an满足a1=1,且an+1=an/1+an.证明:数列1/an为等差数列,并求出数列an的通项公
已知等差数列{an}满足an+1=an²-nan+1,则an=______.
已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列
数列an满足an+1=3an+n,是否存在适当的a1,使{an}是等差数列,说明理由
【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列{1/an}为等差数列,并求出数列{an
在等差数列{an}中,a1=1,a2=3,an+2=3an+1-2an(n属于N+)证明数列{an+1-an}是等比数列
已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列
数列an中,a1=3,an=(3an-1-2)/an-1,数列bn满足bn=an-2/1-an,证明bn是等比数列 2.
已知等比数列{bn}是公比为q与数列{an}满足bn=3^an,(1)证明数列{an}是等差数列 (2)若b8=3,且数
数列{an}满足a1=1,an=an-1(1+2an)(n-1是下标).1、求证:{1/an}是等差数列;2、若a1a2