1²+2²/1×2+2²+3²/2×3+……+2001²+2002
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1²+2²/1×2+2²+3²/2×3+……+2001²+2002²/2001×2002
![1²+2²/1×2+2²+3²/2×3+……+2001²+2002](/uploads/image/z/1759872-48-2.jpg?t=1%26%23178%3B%2B2%26%23178%3B%2F1%C3%972%2B2%26%23178%3B%2B3%26%23178%3B%2F2%C3%973%2B%E2%80%A6%E2%80%A6%2B2001%26%23178%3B%2B2002%26%23)
/>考察一般项:
[n²+(n+1)²]/[n(n+1)]
=(2n²+2n+1)/(n²+n)
=2 +1/(n²+n)
=2+1/[n(n+1)]
=2+1/n -1/(n+1)
(1²+2²)/(1×2)+(2²+3²)/(2×3)+……+(2001²+2002²)/(2001×2002)
=2+1/1-1/2+2+1/2-1/3+...+2+1/2001-1/2002
=2×2001+(1-1/2+1/2-1/3+...+1/2001-1/2002)
=4002+(1-1/2002)
=4002+2001/2002
=8014005/2002,也是4002又2002分之2001.
[n²+(n+1)²]/[n(n+1)]
=(2n²+2n+1)/(n²+n)
=2 +1/(n²+n)
=2+1/[n(n+1)]
=2+1/n -1/(n+1)
(1²+2²)/(1×2)+(2²+3²)/(2×3)+……+(2001²+2002²)/(2001×2002)
=2+1/1-1/2+2+1/2-1/3+...+2+1/2001-1/2002
=2×2001+(1-1/2+1/2-1/3+...+1/2001-1/2002)
=4002+(1-1/2002)
=4002+2001/2002
=8014005/2002,也是4002又2002分之2001.
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