1.what is the correct formula manipulation to find accelerat
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1.what is the correct formula manipulation to find acceleration when using the equation Vf平方=Vi平方+2ad (Vf就是最终速度,Vi是初始速度,a表示加速度,d表示距离)
A(Vf平方-Vi平方)/d B (Vf+Vi)的平方/2d
C (Vf平方+Vi平方)/2d D (Vf平方-Vi平方)/2d
2.the graph shows the motion of a farmer's truck.what is the truck's total displacement?assume that north is the positive direction.
A 150m south B 300m north
C 125m north D 600m south
![](http://img.wesiedu.com/upload/8/4e/84ea62fc3654fba977052d73af8586d3.jpg)
3、How can the instantaneous acceleration of an objevt with varying acceleration be calculated?
A by calculating the slope pf the tangent on a distance-time graph
B by calculating thearea under the graph on a distance-time graph
D by calculating thearea under the graph on a velocity-time graph
C by calculating the slope pf the tangent on a velocity-time graph
A(Vf平方-Vi平方)/d B (Vf+Vi)的平方/2d
C (Vf平方+Vi平方)/2d D (Vf平方-Vi平方)/2d
2.the graph shows the motion of a farmer's truck.what is the truck's total displacement?assume that north is the positive direction.
A 150m south B 300m north
C 125m north D 600m south
![](http://img.wesiedu.com/upload/8/4e/84ea62fc3654fba977052d73af8586d3.jpg)
3、How can the instantaneous acceleration of an objevt with varying acceleration be calculated?
A by calculating the slope pf the tangent on a distance-time graph
B by calculating thearea under the graph on a distance-time graph
D by calculating thearea under the graph on a velocity-time graph
C by calculating the slope pf the tangent on a velocity-time graph
![1.what is the correct formula manipulation to find accelerat](/uploads/image/z/2205218-2-8.jpg?t=1.what+is+the+correct+formula+manipulation+to+find+accelerat)
1,D(问你当使用后面的公式计算加速度时,下面那个公式是正确的)
2,C(下图说的是一辆农民的卡车的运动,问你总位移,假设向北是正方向,即向上)
3,D(问你如何计算变加速度运动的物体的瞬时加速度)(A是计算位移时间曲线的斜率,B是计算位移时间曲线的面积,C是计算速度时间曲线的面积,D是计算速度时间曲线的斜率)
翻译的可能不太好,但意思是对的
希望帮助到您
再问: 第二题为什么选c,怎么算的
再答: 根据对称性,时间轴下面的位移是﹣的,一共是20秒,和5秒到25秒的正的位移面积是完全一样的,几何上对称 所以5秒到45秒内位移为0 而0到5秒内的位移为25m/s×5s=125m
2,C(下图说的是一辆农民的卡车的运动,问你总位移,假设向北是正方向,即向上)
3,D(问你如何计算变加速度运动的物体的瞬时加速度)(A是计算位移时间曲线的斜率,B是计算位移时间曲线的面积,C是计算速度时间曲线的面积,D是计算速度时间曲线的斜率)
翻译的可能不太好,但意思是对的
希望帮助到您
再问: 第二题为什么选c,怎么算的
再答: 根据对称性,时间轴下面的位移是﹣的,一共是20秒,和5秒到25秒的正的位移面积是完全一样的,几何上对称 所以5秒到45秒内位移为0 而0到5秒内的位移为25m/s×5s=125m
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